Optimal. Leaf size=95 \[ \frac{(a+b x)^{m+1} (a c (m+1)+b c (m+2) x)^{-m-1}}{a^2 b c^2 (m+1) (m+2)}-\frac{(a+b x)^{m+1} (a c (m+1)+b c (m+2) x)^{-m-2}}{a b c (m+2)} \]
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Rubi [A] time = 0.112567, antiderivative size = 95, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071 \[ \frac{(a+b x)^{m+1} (a c (m+1)+b c (m+2) x)^{-m-1}}{a^2 b c^2 (m+1) (m+2)}-\frac{(a+b x)^{m+1} (a c (m+1)+b c (m+2) x)^{-m-2}}{a b c (m+2)} \]
Antiderivative was successfully verified.
[In] Int[(a + b*x)^m*(a*c*(1 + m) + b*c*(2 + m)*x)^(-3 - m),x]
[Out]
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Rubi in Sympy [A] time = 20.543, size = 80, normalized size = 0.84 \[ - \frac{\left (a + b x\right )^{m + 1} \left (a c \left (m + 1\right ) + b c x \left (m + 2\right )\right )^{- m - 2}}{a b c \left (m + 2\right )} + \frac{\left (a + b x\right )^{m + 1} \left (a c \left (m + 1\right ) + b c x \left (m + 2\right )\right )^{- m - 1}}{a^{2} b c^{2} \left (m + 1\right ) \left (m + 2\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b*x+a)**m*(a*c*(1+m)+b*c*(2+m)*x)**(-3-m),x)
[Out]
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Mathematica [C] time = 0.250216, size = 82, normalized size = 0.86 \[ -\frac{(a+b x)^{m+1} \left (-\frac{b (m+2) x}{a}-m-1\right )^m (c (a (m+1)+b (m+2) x))^{-m} \, _2F_1\left (m+1,m+3;m+2;\frac{(m+2) (a+b x)}{a}\right )}{a^3 b c^3 (m+1)} \]
Antiderivative was successfully verified.
[In] Integrate[(a + b*x)^m*(a*c*(1 + m) + b*c*(2 + m)*x)^(-3 - m),x]
[Out]
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Maple [A] time = 0.007, size = 57, normalized size = 0.6 \[{\frac{ \left ( bx+a \right ) ^{1+m} \left ( bxm+am+2\,bx+a \right ) x \left ( bcxm+acm+2\,bcx+ac \right ) ^{-3-m}}{{a}^{2} \left ( 1+m \right ) }} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b*x+a)^m*(a*c*(1+m)+b*c*(2+m)*x)^(-3-m),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int{\left (b c{\left (m + 2\right )} x + a c{\left (m + 1\right )}\right )}^{-m - 3}{\left (b x + a\right )}^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*c*(m + 2)*x + a*c*(m + 1))^(-m - 3)*(b*x + a)^m,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.242855, size = 115, normalized size = 1.21 \[ \frac{{\left ({\left (b^{2} m + 2 \, b^{2}\right )} x^{3} +{\left (2 \, a b m + 3 \, a b\right )} x^{2} +{\left (a^{2} m + a^{2}\right )} x\right )}{\left (a c m + a c +{\left (b c m + 2 \, b c\right )} x\right )}^{-m - 3}{\left (b x + a\right )}^{m}}{a^{2} m + a^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*c*(m + 2)*x + a*c*(m + 1))^(-m - 3)*(b*x + a)^m,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x+a)**m*(a*c*(1+m)+b*c*(2+m)*x)**(-3-m),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int{\left (b c{\left (m + 2\right )} x + a c{\left (m + 1\right )}\right )}^{-m - 3}{\left (b x + a\right )}^{m}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*c*(m + 2)*x + a*c*(m + 1))^(-m - 3)*(b*x + a)^m,x, algorithm="giac")
[Out]